C- the centre of curvature=radius of a circle
F- focal point: the point where light rays converge= half of the centre of curvature
Principle Axis- perpendicular from the mirror

To determine the reflection of an image two rays can be drawn:
Ray 1) Parallel to the Principle Axis, and then diagonally through the focal point
Ray 2) Diagonally to the mirror, and then parallel to the principle Axis (opposite)

Magnification-Same size, enlarged, diminished
Attitude-Erect or inverted
Position-displacement from mirror surface (ex. Between C and F)
Type-real (in front of mirror) or Virtual (behind mirror)

Image- diminished, inverted, between C and F, real

The Mirror Equation:
1⁄ƒ= 1⁄di + 1⁄do
Where: ƒ= focal length
di= distance of image from mirror
do= distance of object from mirror

Example 1: Using diagram to the right
Determine the distance of the image from the mirror ƒ= 3.00cm do=7.00cm 1⁄di = 1⁄ƒ − 1⁄do 1⁄di = 1⁄3.00cm − 1⁄7.00cm 1⁄di = 0.1905 di = 5.25cm

The Magnification Equation
m = hi⁄ho = −di⁄do
Where: hi= height of image
ho= height of object

Example 2: Using information from previous example
Determine the height of the image
hi⁄ho = -di⁄do
hi⁄1.50cm = −5.25cm⁄7.00cm
hi = 1.13cm

F- focal point: the point where light rays converge= half of the centre of curvature

Principle Axis- perpendicular from the mirror

To determine the reflection of an image two rays can be drawn:

Ray 1) Parallel to the Principle Axis, and then diagonally through the focal point

Ray 2) Diagonally to the mirror, and then parallel to the principle Axis (opposite)

Magnification-Same size, enlarged, diminished

Attitude-Erect or inverted

Position-displacement from mirror surface (ex. Between C and F)

Type-real (in front of mirror) or Virtual (behind mirror)

The Mirror Equation:

1⁄ƒ= 1⁄di + 1⁄do

Where: ƒ= focal length

di= distance of image from mirror

do= distance of object from mirror

Example 1: Using diagram to the right

Determine the distance of the image from the mirror

ƒ= 3.00cm do=7.00cm

1⁄di = 1⁄ƒ − 1⁄do

1⁄di = 1⁄3.00cm − 1⁄7.00cm

1⁄di = 0.1905

di = 5.25cm

The Magnification Equation

m = hi⁄ho = −di⁄do

Where: hi= height of image

ho= height of object

Example 2: Using information from previous example

Determine the height of the image

hi⁄ho = -di⁄do

hi⁄1.50cm = −5.25cm⁄7.00cm

hi = 1.13cm

Example 3) How to draw a ray diagram